Honor Harrington's Universe

Date conversion problems


I have noticed inconsistencies between day length, year length,
number of days per year, etc.

The problem is that Weber's numbers (More Than Honor p.336) 
contradict each others.

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With my assumptions (taken from MTH p. 335-337) 

- March 21, 1416 PD equals First 1, 1 AL (Manticoran style). 
- March 3, 1900 PD equals Fourth 25, 280 AL. 
- The Manticoran year is 673 local days, with every third a
  leap year of 674 days. 
- The Manticoran year has 18 months of 37 or 38 days each. 

I get these numbers for length of Manticoran year and day:

The Manticoran year is 1.7333 T-years,
or 633.0831 T-days,
or 673.3333 M-days.

The Manticoran day is 0.9402 T-days,
or 22.5653 hours,
or 22 hours 33.9203 min,
or 22 hours 34 minutes.

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David Weber has stated (the table p. 336 in MTH) that the
Manticoran year is 673.31 M-days, to get close to that we
need a more complicated leap year rule.

If we assume that every 3:rd year, except those divisible
by 42 is a leap year, we get these numbers for length of
Manticoran year and day:

The Manticoran year is 1.7333 T-years,
or633.0803 T-days,
or 673.3111 M-days.

The Manticoran day is 0.9403 T-days,
or 22.5661 hours,
or 22 hours 33.9635 min,
or 22 hours 34 minutes. 

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But to get a Manticoran day of 22.45 hours (22 h, 27 m) the
M-year needs to be 676.8 M-days long.

And assuming that landing did not happen at 01-01-01 AL, but
late in year 1 AL does not help, because that will actually
make the M-day longer.

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We might instead assume that the M-day is exactly 22.45 hours,
and ignore that 280-04-25 AL is supposed to equal 1900-03-03 PD.

Then 280-04-25 AL will equal 1897-09-11 PD, and we get these
numbers for length of Manticoran year and day:

The Manticoran year is 1.7245 T-years,
or 629.8472 T-days,
or 673.3333 M-days.

The Manticoran day is 0.9354 T-days,
or 22.4500 hours,
or 22 hours 27.0000 min,
or 22 hours 27 minutes. 

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So one can see that there are inconsistencies.

// 1998-07-30 Bo Johansson